In the MBA Programme of a B – School, there are two sections A and B. 1/4th of the students in Section A and 4/9th of the students in section B are girls. If two students are chosen at random, one each from section A and Section B as class representative, the probability that exactly one of the students chosen is a girl, is:
Explanation:
Selecting a girl from section A and section B is 1/4 and 4/9 respectively.
Selecting a boy from section A and section B is 3/4 and 5/9 respectively.
Case 1: A girl from section A and a boy from section B.
P1 = (1/4) × (5/9) = 5/36
Case 2: A boy from section A and a girl from section B.
P2 = (3/4) × (4/9) = 12/36
Required probability = P1 + P2 =17/36
Hence, option (d).
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