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Explanation:

Sum of numbers before x = sum of numbers after x

∴ 1 + 2 + 3 + … + (x – 1) = (x + 1) + (x + 2) + … + 49

Adding (1 + 2 + 3 + 4 + … + (x – 1) + x) on both sides

∴ 2(1 + 2 + 3 + … +(x – 1)) + x = (1 + 2 + 3 + … + 49)

∴ 2×(x-1)x2 + x = 49×502

∴ x2 = 49 × 25

∴ x = 7× 5 = 35

Hence, option (c).

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