The smallest perfect square that is divisible by 7!
Explanation:
7! = 24 × 32 × 5 × 7
The required perfect square should be divisible by 16, 9, 5 and 7.
16 and 9 are already squares. Since 5 and 7 are not perfect squares, we multiply 7! by 5 and 7 to make it a perfect square.
So required perfect square =24 × 32 × 52 × 72 = 176400
Hence, option (b).
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