For some positive ral number x, if log3 (x) + logx 25logx (0.008) = 163, then the value of log3 (3x2) is
Explanation:
Given, log3 (x) + logx 25logx (0.008) = 163
⇒ log31/2 (x) + logx 52logx (5)-3 = 163
⇒ 2×log3 (x) + 2×logx 5-3×logx (5) = 163
⇒ 2×log3 (x) - 23 = 163
⇒ 2×log3 (x) = 163 + 23 = 6
⇒ log3 x = 3
⇒ x = 27
Now, log3 (3x2) = log3 (3×272) = log3 (37) = 7
Hence, 7.
Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.