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Explanation:

Total 12 goals were scored by 4 players such that each player scored at least one goal and distinct number of total goals.

There are two possibilities for this:
12 = 1 + 2 + 3 + 6
12 = 1 + 2 + 4 + 5

From (1): Only one goal was scored in every even numbered match. 

From (5): An equal number of goals were scored in Match 3 and Match 7, which was different from the number of goals scored in either Match 1 or Match 5.
Let the number of goals scored in Match 3 and 7 be x each.

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From (6): The match in which the highest number of goals was scored was unique and it was not Match 5.
⇒ Highest goals were scored in Match 1.

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From (4): Bimla scored a goal in Match 1 and one each in three other consecutive matches.
From (2): Harita scored more goals than Bimla.
⇒ Bimla scored at least 4 goals while Harita scored at least 5 goals.
∴ 12 = 1 + 2 + 4 + 5
⇒ Bimla scored 4 goals while Harita scored at 5 goals.

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From (3): The highest goal scorer scored goals in exactly 3 matches including Match 4 and Match 8.
∴ Harita can score maximum 1 goal each in Match 4 and 5, hence she scores 3 goals in one more Match.
The only match Harita can score 3 goals is Match 1 since highest numbers of goals are scored in Match 1.

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From (4): Bimla scored a goal in Match 1 and one each in three other consecutive matches.
∴ Three consecutive matches Bimla can score in are Match 5, 6 and 7.

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Now, a + 1 + x + 1 + b + 1 + x + 1 = 12
⇒ a + b + 2x = 8

[Match 7: x has to be greater than or equal to 1.]

Case 1: x = 1
⇒ a + b = 6
⇒ a = 4 and b = 2 [a has to be uniquely highest and a, b ≠ x]

Case 2: x = 2
⇒ a + b = 4
Rejected as minimum value of a is 4 and that of b is 1.

∴ x = 1, a = 4 and b = 2

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Amla or Sarita could have scored 1 or 2 goal in any order.

Number of goals scored in Match 7 = 1.

Hence, option (d).

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