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Explanation:

Let the cost of each apple be ‘a’, each orange be ‘o’ and each mango be ‘m’.

∴ 2a + 4o + 6m = a + 4o + 8m = 8o + 7m

⇒ 2a + 4o + 6m = 8o + 7m
⇒ 4o + m = 2a   …(1)

Also, a + 4o + 8m = 8o + 7m
⇒ 4o – m = a   …(2)

Solving (1) and (2) we get
8o = 3a and m = a/2

∴ Value of each basked in terms of mangoes
= 2a + 4o + 6m
= 4m + 3a/2 + 6m
= 10m + 3/2 × 2m
= 10m + 3m
= 13m

∴ Value of each basket is same as value of 13 mangoes.

Hence, option (a).

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