What is the percentage of votes polled in total by all the candidates who lost their security deposits while contesting for constituency A?
Explanation:
The first runner up polled 10,000 more votes than the second runner up in constituency A.
⇒ Votes polled by the second runner-up = 95,000 – 10,000 = 85,000
∴ Total number of votes polled by the top three candidates in A = 2,75,000 + 95,000 + 85,000 = 4,55,000.
Votes polled by remaining 7 candidates = 5,00,000 – 4,55,000 = 45,000 (This is less than one-sixth of the total votes polled)
⇒ Each of the remaining gets polled less than one-sixth of the total polls in A.
∴ Last 7 candidates lose their security deposits and they polled a total of 45,000 votes.
⇒ Percentage of votes polled in total by all the candidates who lost their security deposits while contesting for constituency A = 45000/500000 × 100 = 9%
Hence, 9.
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