Please submit your concern

Explanation:

Let the number of men subscribers in 2003 be m, and the number of women subscribers in 2003 be w.

It is given that the women subscribers increase at the rate of 10% per year and the men increase at the rate of 5% per year.

∴ Number of men subscribers in 2007 = m(1 + 0.05)7 ≈ m[1 + 7C1 (0.05) + 7C2 (0.05)2 + 7C3 (0.05)3]

≈ m(1 + 0.35 + 0.0525 + 0.0043)

≈ 1.4m

Number of women subscribers in 2007 = w(1 + 0.1)w [1 + 7C1(0.1) + 7C2 (0.1)2 + 7C3 (0.1)3]

≈ w1+7(0.1)+7×62(0.1)2+7×6×52×3(0.1)3

≈ w(1 + 0.7 + 0.21 + 0.035)

≈ 1.95w

Now, it is given that in 2003, men are 60% of the total European subscribers. So, women are 40% of the subscribers. Let the total European subscribers be P. Then,

m = 0.6P and

w = 0.4P

∴ The total number of subscribers in 2003 = m + w = 0.6P + 0.4P = P

And the total number of subscribers in 2007 = 1.4m + 1.95w

= 1.4(0.6P) + 1.95(0.4P)

= 0.84P + 0.78P = 1.62P

∴ Percentage growth of subscribers between '03 and '07 = (1.62)P-PP × 100 = 62%

Hence, option (a).

Feedback

Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.


© 2024 | All Rights Reserved | Apti4All