Using only 2, 5, 10, 25 and 50 paise coins, what will be the minimum number of coins required to pay exactly 78 paise, 69 paise and Rs 1.01 to three different persons?
Explanation:
Case1: To pay 78 paise using minimum number of coins:
78 = 1(50) + 2(10) + 4(2), i.e. a total of 7 coins were used
Case 2: To pay 69 paise using minimum number of coins:
69 = 1(50) + 1(10) + 1(5) + 2(2), i.e. a total of 5 coins were used
Case 3: To pay 101 paise using minimum number of coins:
101 = 1(50) + 1(25) + 2(10) + 3(2), i.e. a total of 7 coins were used
∴ Minimum coins used were 7 + 5 + 7 = 19 coins
Hence, option (a).
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