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Explanation:

The radius of each circular park = r

A1B1 = A1E = r

Distance travelled by A = a = 3 × 2r = 6r

∆A1B1D is a right angle triangle with ∠A1B1D = 30° and ∠B1A1D = 60°

∴ B1D = 3r2

∴B1B2 = 2r + 2 × r32=r(2+3)

∴ Distance travelled by B = b = 3r(2 + 3)

Similarly, ∆A1C1E is a right angle triangle with ∠A1C1E = 30° and ∠C1A1E = 60°

∴ C1E = r3

∴ C1C2 = 2r + 2r3=2r(1+3)

∴ Distance travelled by C = c = 6r(1 + 3)

∴ b - a = 33r and c - b = 33r

Hence, option (a).

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