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Explanation:

Let a = no. of males in Chota hazri, b = no. of males in Mota hazri, x = no. of females in Chota hazri and y = no. of females in Mota hazri

∴ a + 4522 = b                               ...(i)

∴ y = b + 4020                              ...(ii)

∴ x = 2a                                        ...(iii)

∴ x = y – 2910                               ...(iv)

Using (iv), (ii)  and (iii), we have,

2a = b + 4020 – 2910

Substituting from (i), we have,

2a = a + 4522 + 4020 – 2910

a  = 5632

Hence, option (c).

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