Please submit your concern

Explanation:

f (x,y) = |x + y| − − − This is always positive
F(f (x,y)) = − f (x,y) = −|x + y| − − − This is always negative
G(f (x,y)) = − F(f (x,y)) = − (−|x + y|) = |x + y| − − − This is always positive.

The option (c) yields x².

-F(f(x, x)) ∙ G(f(x, x)) ÷ log₂ 16

= -(-2x ∙ 2x) ÷ log₂ 16

= $\frac{4x^2}{{\log }_2{2}^4}=x^2$