Given odd positive integers x, y and z, which of the following is not necessarily true?
Explanation:
You can solve this by assuming values of x, y and z.
Let the three numbers be 1, 3 & 5.
Option (a) is 12 32 52 = 225, which is odd.
Option (b) is 3(12 + 33)52 = 2100, which is even.
Option (c) is 5 + 3 + 54 = 633, which is odd.
Option (d) is 52(14+34)2= 1025, which is not even and hence, the answer.
Hence, option (d).
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