Let the consecutive vertices of a square S be A, B, C & D. Let E, F & G be the mid-points of the sides AB, BC & AD respectively of the square. Then the ratio of the area of the quadrilateral EFDG to that of the square S is nearest to
Explanation:
Let the side of square be a.
Area of quadrilateral EFDG = Ar(△DGF) + Ar(△GEF) = 1/2 × a/2 × a + 1/2 × a × a/2 = 1/2 × a2
Ar(EFDG) : Ar(S) = 1/2 × a2 : a2 = 1 : 2
Hence, option (a).
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