Discussion

Explanation:

Let Raju and Lalitha originally had (4x) and (9x) marbles. Later Lalitha gave (y) marbles to Raju.

Therefore, $\frac{4x+y}{9x-y}$ = $\frac{5}{6}$

⇒ 6(4x + y) = 5(9x - y)
⇒ 24x + 6y = 45x - 5y
⇒ 11y = 21x
​​​​​​​∴ y = 21x/11

The required fraction = y/9x = $\frac{{\displaystyle \frac{21}{11}}x}{9x}$ = $\frac{7}{33}$

Hence, option (c).

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