If (2n+1) + (2n+3) + (2n+5) + ... + (2n+47) = 5280 , then what is the value of 1 + 2 + 3 + ... + n?
Explanation:
Given: (2n + 1) + (2n + 3) + (2n + 5) + ... + (2n + 47) = 5280
⇒ (2n + 2n +.... + 2n) + (1 +3 + 5 +.... + 47) = 5280
Odd numbers from 1 to 47 are added in the above series.
nth odd natural number = 2n - 1
∴ Number of terms from 1 to 47 = (47 + 1)/2 = 24 terms
∴ Given equation becomes 2n × 24 + (1 + 3 + 5 + … + 47) = 5280
Sum of first n odd natural numbers = n2.
⇒ 2n × 24 + 242 = 5280
⇒ 2n × 24 = 5280 - 242
⇒ 2n = 220 - 24
⇒ n = 98
Hence, 1 + 2 + 3 + ... + 98 = 98×992 = 4851.
Hence, 4851.
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