Discussion

Question:

A chemist mixes two liquids 1 and 2. One litre of liquid 1 weighs 1 kg and one litre of liquid 2 weighs 800 gm. If half litre of the mixture weighs 480 gm, then the percentage of liquid 1 in the mixture, in terms of volume, is

Explanation:

Density of liquid 1 = 1000 g/L.

Density of liquid 2 = 800 g/L.

Half litre of the mixture weighs 480 gm, so 1 L of the mixture weighs 960 gm.

So, density of the mixture = 960 g/L.

Using the alligation cross;

$\frac{L i q u i d 1}{L i q u i d 2} = \frac{(960 - 800)}{(1000 - 960)}$ = $\frac{4}{1}$ .

Percentage of liquid 1 in the mixture = (4/5) × 100 = 80%.

Hence, option (c).

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