If 1067 – 87 is written as an integer in base 10 notation, what is the sum of digits in that integer?
Explanation:
1067 is nothing but 10...00000 (67 times) i.e. 1 followed by 67 0s. When a two-digit number is subtracted from it, the last two 0s get replaced by (100 − that two-digit number number) while the remaining 0s get replaced by 9s due to carry of the subtraction. Hence, when 87 is subtracted from a number having 67 0s, we get 67 − 2 = 65 9s and the last two digits as 100 − 87 = 13. ∴ Sum of digits = 65(9) + 1 + 3 = 589 Hence, option (d).
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