If a, b and c are 3 consecutive integers between –10 to +10 (both inclusive), how many integer values are possible for the expression a3+b3+c3+3abc(a+b+c)2?
Explanation:
If a, b and c are three consecutive numbers ⇒ a = b – 1 and c = b + 1
Substituting this in the expression we get the expression we get,
= (b-1)3+b3+(b+1)3+3(b-1)b(b+1)(b-1+b+b+1)2
= 6b3+3b(3b)2
= 2b2+13b
Only for b = ±1 is the above expression an integer.
Hence, option (c).
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