Discussion

Explanation:

If a, b and c are three consecutive numbers
⇒ a = b – 1 and c = b + 1

Substituting this in the expression we get the expression we get,

(b-1)3+b3+(b+1)3+3(b-1)b(b+1)(b-1+b+b+1)2

= 6b3+3b(3b)2

= 2b2+13b

Only for b = ±1 is the above expression an integer.

Hence, option (c).

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