Discussion

Explanation:

(2061)B = (1 + 6B + 2B3)10

(601)B = (1 + 6B2)10

∴ 2B3 + 6B2 + 6B + 2 = 432

⇒ B3 + 3B2 + 3B + 1 = 216

⇒ (B + 1)3 = 216

⇒ B = 5

∴ 10105 = (1 × 53 + 1 × 5)10 = 13010

Hence, option (c).

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