1#1#2-(101.3∇log100.1)(1∇2)=
Explanation:
Let us first simplify the numerator. Since 1 is positive, (1 # 1) is 1 + 1 = 2 which again is positive. Then (1 # 1) # 2 = 2 # 2 = 2 + 2 = 4 Now note that log10 0.1 = log10 10–1 = –1 Then 101.3 log10 0.1= 101.3 × (–1) is negative. So 101.3 ∇ log10 0.1 = 1 Hence, the numerator is equal to 4 –1 = 3 Since 1 × 2 = 2 is positive, (1∇2) = (1× 2)1+2 = 23 = 8. So the denominator = 8. Hence, the answer is 38.
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