If n is an integer, how many values of n will give an integral value of (16n2+7n+6)n?
Explanation:
The given expression can be written as
16n2n+7nn+6n=16n+7+6n
Since n is an integer, the expression (16n + 7) will always be an integer. Hence, for the entire expression to be an integer, the part 6n should also be an integer. This can be possible only if n is a factor of 6, viz. n = 1, 2, 3, 6, –1, –2, –3 and –6.
Hence, n can have eight values.
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