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Question:

In a company, 20% of the employees work in the manufacturing department. If the total salary obtained by all the manufacturing employees is one-sixth of the total salary obtained by all the employees in the company, then the ratio of the average salary obtained by the manufacturing employees to the average salary obtained by the nonmanufacturing employ

Explanation:

Let the total number of employees be 100 and their average salary be s.

⇒ There are 20 manufacturing employees and 80 non-manufacturing
Let the average salary of manufacturing employees be 'x' and that of non-manufacturing employees be 'y'.

Total Salary of manufacturing employees is one-sixth that of total employees:
∴ 20 × x = 1/6 × 100 × s
⇒ x = 5s/6

Total Salary of nonmanufacturing employees is five-sixth that of total employees:
∴ 80 × x = 5/6 × 100 × s
⇒ x = 25s/24

The ratio of the average salary obtained by the manufacturing employees to the average salary obtained by the non-manufacturing employee = 5s/6 : 25s/24 = 4 : 5.

Hence, option (a).

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Doubts

Meenakshi said (2024-05-19 05:30:04)

Why is the total number of employees assumed as 100?

Reply from Admin:

Since we have to find out ratio we can start with assuming some number of employees to make calculations easy.

You could also assume number of employees as 'x' and solve it. That will also give the same answer as 'x' will get cancelled out while calculating the required ratio.

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