Discussion

Explanation:

Let 20 kgs and 30 kgs of A and B are mixed.
∴ Amount of sugar in C = 2/5 × 20 + 3/10 × 30 = 17 kgs

Now we have 50 kgs of C mixed with 50 kgs of milk i.e., 100 kgs of final solution.

⇒ Concentration of sugar in final solution = 17/(50 + 50) × 100% = 17%

Hence, option (b).

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