Rajesh, a courier delivery agent, starts at point A and makes a delivery each at points B, C and D, in that order. He travels in a straight line between any two consecutive points. The following are known:
(i) AB and CD intersect at a right angle at E, and
(ii) BC, CE and ED are respectively 1.3 km, 0.5 km and 2.5 km long.
If AD is parallel to BC, then what is the total distance (in km) that Rajesh covers in travelling from A to D?
Explanation:
Given, CE = 0.5, BC = 1.3 and ED = 2.5 Triangle CEB is a right-angled triangle ⇒ EB = 1.2 Triangles ECB is similar to triangle EDA EB/EC = AE/ED ⇒ AE = 6 Hence total distance travelled = AB + BC + CD = 7.2 + 1.3 + 3.5 = 11.5km
» Your doubt will be displayed only after approval.
Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.