Discussion

Explanation:

AC=242+232=40

Let us draw DE, which is perpendicular to AC.

Since ΔADC is isosceles, therefore DE will be its median and altitude both.

∴ DE = 252-202=15

∴ Required area = 12×24×32+12×40×15 = 384 + 300 = 684

Hence, option (d).

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