Discussion

Explanation:

Let the speed of Rahul in still water be p and speed of current be q miles per hour.

12(p+q)=12(p-q)-6 ...(i)

12(2p+q)=12(2p-q)-1 ...(ii)

12p − 12q = 12p + 12q − 6(p − q)(p + q)

On solving, we get,

4q = p2 − q2                                    … (iii)

24p – 12q = 24p + 12q – (4p2 − q2)

On solving we get,

4p2 − q2 = 24q                                … (iv)

Solving (iii) and (iv), we get,

24q = 9q2

q=83

Hence, option (d).

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