Discussion

Question:

In the above diagram, ABCD is a rectangle with AE = EF = FB. What is the ratio of the area of the triangle CEF and that of the rectangle?

Explanation:

∵ AB = 3 × EF

$\frac{A r e a o f (∆ C E F)}{A r e a o f (□ A B C D)} = \frac{\frac{1}{2} \times E F \times C B}{A B \times C B}$

$\frac{A r e a o f (∆ C E F)}{A r e a o f (□ A B C D)} = \frac{\frac{1}{2} \times E F \times C B}{3 \times E F \times C B} = \frac{1}{6}$

Hence, option (a).

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