Discussion

Explanation:

Let the number of 100, 250 and 500 notes be a, b and c respectively.

⇒ a + b + c = 100   …(1)

⇒ 100a + 250b + 500c = 15250
⇒ 2a + 5b + 10c = 305   …(2)

(2) – 2 × (1)
⇒ 3b + 8c = 105
⇒ c = $\frac{105-3\mathrm{b}}{8}$ = $\frac{104+1-3\mathrm{b}}{8}$ = 13 + $\frac{1-3\mathrm{b}}{8}$

c will be maximum when b is minimum. The least value b can take such that c is integer is 3. 

∴ c = 13 + $\frac{1-9}{8}$ = 12

Hence, 12.

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