Discussion

Explanation:

Total marks of all 5 students = 5 × 38 = 190

Case 1: Least marks of Amit.
To minimize Amit’s marks we should maximize the marks of other 4 students.
⇒ 3 students get more than 32, hence their maximum marks can be 48, 49 and 50. [Marks are distinct]

2 students (including Amit) scored less than or equal to 32.
⇒ Maximum marks of 2nd student can be 32

∴ Sum of marks of these 4 students = 32 + 48 + 49 + 50 = 179
⇒ Least marks of Amit = 190 – 179 = 11

Case 2: Maximum marks of Amit.
Since Amit and one other student scored less than or equal to 32 marks, maximum marks Amit can score is 31. [Amit scored least and all scores are distinct.]

∴ Difference between highest and least score of Amit = 31 – 11 = 20

Hence, option (b).

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