Suppose there is a second station with raw material for the robot at the other extreme of the line which is 60 metres from the origin, that is, 10 metres from E. After finishing the services in a trip, the robot returns to the nearest station. If both stations are equidistant, it chooses the origin as the station to return to. Assuming that both stations receive the messages sent by the machines and that all the other data remains the same, what would be the answer to the above question?
Explanation:
Machines A and D sent message at the beginning of the first second.
∴ Round 1: Origin 1 to Machine A to Machine D to Origin 2
Distance covered by the robot = 10 m + 30 m + 20 m = 60 m
Time taken for round 1 = 6 seconds
At the end of 6th second, messages from C and B are already received,
∴ Round 2: Origin 2 to Machine C to Machine B to Origin 1
Distance covered by the robot = 30 m + 10 m + 20 m = 60 m
Time taken to return to origin = 6 seconds
Total Time elapsed = 6 + 6 = 12 seconds
At the end of 12th second, message from E is already there.
The robot has travelled 120 m (60 m + 60 m), when it notices message from E.
Hence, option (a).
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