Ravindra and Rekha got married 10 years ago, their ages were in the ratio of 5 : 4. Today Ravindra’s age is one sixth more than Rekha’s age. After marriage, they had 6 children including a triplet and twins. The age of the triplets, twins and the sixth child is in the ratio of 3 : 2 : 1. What is the largest possible value of the present total age of the family?
Explanation:
Let the present age of Ravindra and Rekha be Rv and Re respectively.
Rv-10Re-10 = 54
Rv = (1 + 1/6)Re Solving these equations, we get Rv = 35 and Re = 30 Maximum age of a child = 9 years (10 year after marriage) To maximize the age of family, Age of triplets = 9 years, twins = 6 years and sixth child = 3 years Age of the family = 35 + 30 + (9 × 3) + (6 × 2) + 3 = 107 Hence, option (d).
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