Discussion

Explanation:

Let the amount on Shailaja’s cheque be Rs. x and paise y = (100x + y) paise (x and y are positive integers)

The teller gives her (100y + x) paise.

Now, 100y + x – 50 = 3(100x + y)

∴ 97y – 299x = 50

∴ y = (50 + 299x)/97 = [50 + 8x + 291x]/97 = [(50 + 8x)/97] + 3x

Now as y is an integer, (50 + 8x) has to be a multiple of 97 with x, y ≤ 99

50 + 8x = 97k (k is an integer)
∴ k = 2, 10, 18…
∴ x = 18, 115, 212…
​​​​​​​∴ x = 18 is the only possible value.

This implies that y = 5

∴ The amount on Shailaja’s cheque is over Rs. 18 but less than Rs. 19.

Hence, option (d).

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